bash-hackers-wiki/docs/commands/builtin/unset.md

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# The unset builtin command
## Synopsis
unset [-f|v] [-n] [NAME ...]
## Description
The `unset` builtin command is used to unset values and attributes of
shell variables and functions. Without any option, `unset` tries to
unset a variable first, then a function.
### Options
|Option|Description|
|------|-----------|
|`-f`|treats each `NAME` as a function name|
|`-v`|treats each `NAME` as a variable name|
|`-n`|treats each `NAME` as a name reference and unsets the variable itself rather than the variable it references|
### Exit status
|Status|Reason|
|------|------|
|0|no error|
|!=0|invalid option|
|!=0|invalid combination of options (`-v` **and** `-f`)|
|!=0|a given `NAME` is read-only|
## Examples
unset -v EDITOR
unset -f myfunc1 myfunc2
### Scope
In bash, unset has some interesting properties due to its unique dynamic
scope. If a local variable is both declared and unset (by calling unset
on the local) from within the same function scope, then the variable
appears unset to that scope and all child scopes until either returning
from the function, or another local variable of the same name is
declared underneath where the original variable was unset. In other
words, the variable looks unset to everything until returning from the
function in which the variable was set (and unset), at which point
variables of the same name from higher scopes are uncovered and
accessible once again.
If however unset is called from a child scope relative to where a local
variable has been set, then the variable of the same name in the
next-outermost scope becomes visible to its scope and all children - as
if the variable that was unset was never set to begin with. This
property allows looking upwards through the stack as variable names are
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unset, so long as unset and the local it unsets aren't together in the
same scope level.
Here's a demonstration of this behavior.
#!/usr/bin/env bash
FUNCNEST=10
# Direct recursion depth.
# Search up the stack for the first non-FUNCNAME[1] and count how deep we are.
callDepth() {
# Strip "main" off the end of FUNCNAME[@] if current function is named "main" and
# Bash added an extra "main" for non-interactive scripts.
if [[ main == !(!("${FUNCNAME[1]}")|!("${FUNCNAME[-1]}")) && $- != *i* ]]; then
local -a 'fnames=("${FUNCNAME[@]:1:${#FUNCNAME[@]}-2}")'
else
local -a 'fnames=("${FUNCNAME[@]:1}")'
fi
if (( ! ${#fnames[@]} )); then
printf 0
return
fi
local n
while [[ $fnames == ${fnames[++n]} ]]; do
:
done
printf -- $n
}
# This function is the magic stack walker.
unset2() {
unset -v -- "$@"
}
f() {
local a
if (( (a=$(callDepth)) <= 4 )); then
(( a == 1 )) && unset a
(( a == 2 )) && declare -g a='global scope yo'
f
else
trap 'declare -p a' DEBUG
unset2 a # declare -- a="5"
unset a a # declare -- a="4"
unset a # declare -- a="2"
unset a # ./unset-tests: line 44: declare: a: not found
: # declare -- a="global scope yo"
fi
}
a='global scope'
f
# vim: set fenc=utf-8 ff=unix ts=4 sts=4 sw=4 ft=sh nowrap et:
output:
declare -- a="5"
declare -- a="4"
declare -- a="2"
./unset-tests: line 44: declare: a: not found
declare -- a="global scope yo"
Some things to observe:
- `unset2` is only really needed once. We remain 5 levels deep in
`f`'s for the remaining `unset` calls, which peel away the outer
layers of `a`'s.
- Notice that the "a" is unset using an ordinary unset command at
recursion depth 1, and subsequently calling unset reveals a again in
the global scope, which has since been modified in a lower scope
using declare -g.
- Declaring a global with declare -g bypasses all locals and sets or
modifies the variable of the global scope (outside of all
functions). It has no affect on the visibility of the global.
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- This doesn't apply to individual array elements. If two local
arrays of the same name appear in different scopes, the entire array
of the inner scope needs to be unset before any elements of the
outer array become visible. This makes "unset" and "unset2"
identical for individual array elements, and for arrays as a whole,
unset and unset2 behave as they do for scalar variables.
### Args
Like several other Bash builtins that take parameter names, unset
expands its arguments.
~ $ ( a=({a..d}); unset 'a[2]'; declare -p a )
declare -a a='([0]="a" [1]="b" [3]="d")'
As usual in such cases, it's important to quote the args to avoid
accidental results such as globbing.
~ $ ( a=({a..d}) b=a c=d d=1; set -x; unset "${b}["{2..3}-c\]; declare -p a )
+ unset 'a[2-1]' 'a[3-1]'
+ declare -p a
declare -a a='([0]="a" [3]="d")'
Of course hard to follow indirection is still possible whenever
arithmetic is involved, also as shown above, even without extra
expansions.
In Bash, the `unset` builtin only evaluates array subscripts if the
array itself is set.
~ $ ( unset -v 'a[$(echo a was set >&2)0]' )
~ $ ( a=(); unset -v 'a[$(echo a was set >&2)0]' )
a was set
## Portability considerations
Quoting POSIX:
If neither -f nor -v is specified, name refers to a variable; if a variable by that name does not exist, it is unspecified whether a function by that name, if any, shall be unset.
Therefore, it is recommended to explicitly specify `-f` or `-v` when
using `unset`. Also, I prefer it as a matter of style.
## See also
- [declare](../../commands/builtin/declare.md)
- [unset](../../commands/builtin/unset.md)
- [POSIX `unset`
utility](http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_29)